If each side of a square is increased by 10% the percentage increase in area is
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Solution(By Examveda Team)Let the original length of sides be xThen, new length : $$\eqalign{ & = \left( {110\% {\text{ of }}x} \right) \cr & = \frac{{11x}}{{10}} \cr} $$ Original area $${x^2}$$ New area : $$\eqalign{ & = {\left( {\frac{{11x}}{{10}}} \right)^2} \cr & = \frac{{121{x^2}}}{{100}} \cr} $$ Increase in area : $$\eqalign{ & = \left( {\frac{{121{x^2}}}{{100}} - {x^2}} \right) \cr & = \frac{{21{x^2}}}{{100}} \cr} $$ ∴ Increase % : $$\eqalign{ & = \left( {\frac{{21{x^2}}}{{100}} \times \frac{1}{{{x^2}}} \times 100} \right)\% \cr & = 21\% \cr} $$ What is the percent increase in area of a square if its side is increased by 10% 20%?Expert-Verified Answer
Given that side of square is increased by 10%. Hence, area of square will increase by 21% .
What will be the percentage increase in the area of a square if its side is increased by 20?percentage increase in are =44%
What will be the percentage increase in the area of a square when each of the its sides is increased by 25 %?∴ Percentage change in area is 56.25%
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Is the side of a square be increased by 50% find the percent increase in area?∴ If the length of the side of the square is increased by 50% then the area will increase by 125%.
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