Solution[By Examveda Team]
Let the original length of sides be xThen, new length :
$$\eqalign{ & = \left[ {110\% {\text{ of }}x} \right] \cr & = \frac{{11x}}{{10}} \cr} $$
Original area $${x^2}$$
New area :
$$\eqalign{ & = {\left[ {\frac{{11x}}{{10}}} \right]^2} \cr & = \frac{{121{x^2}}}{{100}} \cr} $$
Increase in area :
$$\eqalign{ & = \left[ {\frac{{121{x^2}}}{{100}} - {x^2}} \right] \cr & = \frac{{21{x^2}}}{{100}} \cr} $$
∴ Increase % :
$$\eqalign{ & = \left[ {\frac{{21{x^2}}}{{100}} \times \frac{1}{{{x^2}}} \times 100} \right]\% \cr & = 21\% \cr} $$
What is the percent increase in area of a square if its side is increased by 10% 20%?
Expert-Verified Answer
Given that side of square is increased by 10%. Hence, area of square will increase by 21% .
What will be the percentage increase in the area of a square if its side is increased by 20?
percentage increase in are =44%
What will be the percentage increase in the area of a square when each of the its sides is increased by 25 %?
∴ Percentage change in area is 56.25%
A total of 330 vacancies were released for the last recruitment cycle and more vacancies are expected to be released for this year.
Is the side of a square be increased by 50% find the percent increase in area?
∴ If the length of the side of the square is increased by 50% then the area will increase by 125%.